When ethanol is converted to ethanoic acid by using acidified potassium dichromate, the ethanol is:

reduced and the colour changes from orange to green

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reduced and the colour changes from green to orange

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oxidised and the colour changes from orange to green

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oxidised and the colour changes from green to orange

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Solution

The correct option is C oxidised and the colour changes from orange to green
(ethanol) $C_{2} H_{5} O H + [O] ⟶ C H_{3} C H O + H_{2} O$
$C H_{3} C H O + [O] ⟶ C H_{3} C O O H$
(ethanoic acid)
This reaction takes place in presence of strong oxidizing agents like $K_{2} C r_{2} O_{7} + (d i l .) H_{2} S O_{4}$
$K_{2} C r_{2} O_{7} o r a n g e + 4 H_{2} S O_{4} (d i l .) ⟶ K_{2} S O_{4} + C r (S O_{4})_{3} g r e e n + 4 H_{2} O + 3 [O]$
This reaction takes place underneath, which provides nascent oxygen. Due to this, color changes from orange to green.

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What happens when SO₂ gas is passed through potassium dichromate solution?

C r_{2} O_{7}^{2 -}

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