When ethanol is subjected to dehydration in presence of $H_{2} {S O}_{4}$ , the intermediate formed is a:

carbonium ion

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carbanion

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radical

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carbene

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Solution

The correct option is C carbonium ion
$C H_{3} - C H_{2} - O H ⟶ C H_{3} - + C H_{2} ⟶ C H_{2} = C H_{2}$
The intermedate formed is a carbonium ion or carbocation

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H_{2} {S O}_{4}

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