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Dehydration of Alcohols

When ethanol ...

Question

When ethanol vapours are passed over alumina heated at $350^{0} C$ , the main product obtained is:

C_{2} H_{6}

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C_{2} H_{4}

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C_{2} H_{2}

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C_{2} H_{5} {O C}_{2} H_{5}

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Solution

The correct option is B $C_{2} H_{4}$
Dehydration of alcohols is done in presence of alumina at $350^{0} - 400^{0}$ and by this process alkene is obtained.

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Similar questions

C_{2} H_{5} {O C}_{2} H_{5} + C O 105^{o} C - ------- \to {B F}_{3}, 500 a t m s X

X

K_{p}

C_{2} H_{4} + H_{2} ⇌ C_{2} H_{6}

5 \times 10^{18} {a t m}^{- 1}

K_{p}

C_{2} H_{2} + H_{2} ⇌ C_{2} H_{4}

5 \times 10^{26} {a t m}^{- 1}

50

K_{p}

2 H_{2} + C_{2} H_{2} ⇌ C_{2} H_{6}

x \times 10^{45}

10 x

C_{2} H_{4} + H_{2} O = C_{2} H_{5} O H

{Δ H}_{f o r m}^{o} (C_{2} H_{4}) = 55, 28 K J / m o l

{Δ H}_{f o r m}^{o} (H_{2} O) = - 241.8 K J / m o l

{Δ H}_{f o r m}^{o} (C_{2} H_{5} O H) = - 235.3 K J / m o l

S - S

C_{2} H_{5} - S - C_{2} H_{5}; Δ H_{f}^{o} = - 147 k J {m o l}^{- 1}

C_{2} H_{5} - S - S - C_{2} H_{5}; Δ H_{f}^{o} = - 201.9 k J {m o l}^{- 1}

S (g) - Δ H_{f}^{o} = - 222.8 k J {m o l}^{- 1}

C_{2} H_{4} + H_{2} ⟶ C_{2} H_{6}

C_{2} H_{4}; C_{λ} H_{6} . & H_{2} a r e - 140.1 K g, - 1550 K g & - 286.0 K g | m o l

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