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Free Radical Halogenation

When ethyl al...

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When ethyl alcohol and acetic acid mixed together in equimolecular proportion equilibrium is attained when two third of the acid and alcohol are consumed. The equilibrium constant of the reaction will be

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Q. When ethyl alcohol and acetic acid mixed together in equimolecular proportions, equilibrium is attained when two - thirds of the acid and alcohol are consumed. The equilibrium constant of the reaction will be:

1.0 m o l e

of ethyl alcohol and

1.0 m o l e

of acetic acid are mixed. At equilibrium,

0.666 m o l e

of ester is formed. The value of equilibrium constant is:

1.0

mole of ethyl alcohol and

1.0

mole of acetic acid are mixed. At equilibrium,

0.666

mole of ester is formed. The value of equilibrium constant is:

Q. If different quantities of ethyl alcohol and acetic acid are used in the reversible reaction

C H_{3} C O O H + C_{2} H_{5} O H \Leftrightarrow C H_{3} C O O C_{2} H_{5} + H_{2} O

then the equilibrium constant will have the values:

3 m o l e s

of ethyl alcohol are mixed with

3 m o l e s

of acetic acid,

2 m o l e s

of ester are formed at equilibrium according to the equation:

C H_{3} C O O H (l) + C_{2} H_{5} O H (l) ⇌ C H_{3} C O O C_{2} H_{5} (l) + H_{2} O (l)

The value of the equilibrium constant for the reaction is:

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