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Question

When ethyl chloride and alcoholic KOH are heated, the compound obtained is

A
C6H6
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B
C2H6
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C
C2H2
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D
C2H4
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Solution

The correct option is D C2H4
There are two types of elimination reaction,
1. α Elimination reaction
2. β Elimination reaction

In α Elimination reaction, the leaving group and the proton are removed from the same α carbon which leads to reactive carbene intermediate.
In β Elimination reaction, the leaving group and the proton are removed from the adjacent atoms i.e., leaving group from α carbon and proton from β carbon. It leads to the formation of alkene compounds.
We know that,
When ethyl chloride is heated in presence of alcoholic KOH it undergo dehydrohalogenation to give alkene product. This reaction is a β Elimination reaction.

CH3CH2Cl+KOHCH2=CH2+KCl+H2O
Thus, in the given reaction ethene (C2H4) is produced.

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