1
Question
When ethyl chloride and alcoholic KOH are heated, the compound obtained is
When ethyl chloride and alcoholic KOH are heated, the compound obtained is
Open in App
Solution
The correct option is D C2H4
There are two types of elimination reaction,
1. α− Elimination reaction
2. β− Elimination reaction
In α− Elimination reaction, the leaving group and the proton are removed from the same α− carbon which leads to reactive carbene intermediate.
In β− Elimination reaction, the leaving group and the proton are removed from the adjacent atoms i.e., leaving group from α− carbon and proton from β− carbon. It leads to the formation of alkene compounds.
We know that,
When ethyl chloride is heated in presence of alcoholic KOH it undergo dehydrohalogenation to give alkene product. This reaction is a β− Elimination reaction.
CH3CH2Cl+KOH→CH2=CH2+KCl+H2O
Thus, in the given reaction ethene (C2H4) is produced.
There are two types of elimination reaction,
1. α− Elimination reaction
2. β− Elimination reaction
In α− Elimination reaction, the leaving group and the proton are removed from the same α− carbon which leads to reactive carbene intermediate.
In β− Elimination reaction, the leaving group and the proton are removed from the adjacent atoms i.e., leaving group from α− carbon and proton from β− carbon. It leads to the formation of alkene compounds.
We know that,
When ethyl chloride is heated in presence of alcoholic KOH it undergo dehydrohalogenation to give alkene product. This reaction is a β− Elimination reaction.
CH3CH2Cl+KOH→CH2=CH2+KCl+H2O
Thus, in the given reaction ethene (C2H4) is produced.
Suggest Corrections
0
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
