When ethyl iodide is heated with silver nitrate, the product obtained is

C_{2} H_{5} A g

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A g - O - {N O}_{2}

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C_{2} H_{5} O - {N O}_{2}

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C_{2} H_{5} 1 - {N O}_{2}

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Solution

The correct option is B $C_{2} H_{5} O - {N O}_{2}$
$C_{2} H_{5} - I + A g N O_{3} \to C_{2} H_{5} O - N O_{2} + A g l$
Hence C is correct answer

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