When ethyl iodide is treated with alcoholic potash, we get :

Ethyl alcohol

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Ethane

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Acetylene

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Ethylene

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Solution

The correct option is B Ethylene
When ethyl iodide is reacted with alcoholic potash we get ethylene. This reaction is called as dehydro halogenation which is a elimination reaction. This is a process of preparing alkenes from haloalkanes.
$C H_{3} - C H_{2} - I$ + alc $K O H$ $\to$ $C H_{2} = C H_{2}$ + $K I$ + $H_{2} O$

Hence option D is correct.

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