When Ethyl magnesium bromide is treated with heavy water, the expected compound will be

$C_{2}$ $H_{5}$ D

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$C_{2}$ $H_{5}$ OD

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$C_{2}$ $D_{6}$

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$C_{2}$ $H_{3}$ $D_{3}$

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Solution

The correct option is A
$C_{2}$ $H_{5}$ D

R group of the Grignard reagent combines with hydrogen of water

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Similar questions

When Ethyl magnesium bromide is treated with heavy water, the expected compound will be

A g_{2} O

C_{2} H_{5} - N = C = O

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