When ethylene bromide is treated with Zn we get

Alkane

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Alkene

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Alkyne

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All

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Solution

The correct option is B
Alkene

$C H_{2} - C H_{2} + Z n \to C H_{2} = C H_{2} + B r_{2} | | A l k e n e B r B r$

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Similar questions

Write the molecular formula of (i) an alkane (ii) an alkene, and (iii) an alkyne, each having 20 carbon atoms.

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