When excess of ammonia is used:

$3 C l_{2} + 8 N H_{3}$ $⟶$ $A + B$

When excess of chlorine is used:

$3 C l_{2} + 4 N H_{3}$ $⟶$ $C + D$

The oxidation state of nitrogen in compound $D$ is:

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Solution

The correct option is B $+ 3$
$3 {C l}_{2} + 2 {N H}_{3} ⟶ N_{2} (g) + H C l (g)$
$\begin{matrix} when ammonia is excess then H C l + N H_{3} ⟶ N H_{4} C l \end{matrix}$
$\begin{matrix} When chlorine in excess \begin{matrix} 2 {N H}_{3} (g) + 3 {C l}_{2} (g) ⟶ & 2 N^{+ 3} {C l}_{3} (1) + 6 H C l (g) yellow oily liquid \end{matrix} \end{matrix}$
$\begin{matrix} oxidation state of Nitrogen in compound N C l_{3} is + 3 . \end{matrix}$

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Similar questions

Q. When excess of ammonia is used:

3 C l_{2} + 8 N H_{3}

⟶

A + B

When access of chlorine is used:

3 C l_{2} + 4 N H_{3}

⟶

C + D

Oxidation state of nitrogen in compound

B

is:

The weight of chlorine gas undergoing oxidation when excess of chlorine is sent into hot concentrated caustic soda solution containing 24 grams of solute in it
$3 C l_{2} + 6 N a O H \to 5 N a C l + N a C l O_{3} + 3 H_{2} O$

Question 15
Ozone-layer is getting depleted because of

(a) excessive use of automobiles
(b) excessive formation of industrial units
(c) excessive use of man-made compounds containing both fluorine and chlorine
(d) excessive deforestation.

Q. Copy and complete the following equations:
(i) Mg₃N₂ + 6H₂O

\overset{}{\to}

(ii) 2NH₃ + 3CuO

\overset{}{\to}

(iii) 8NH₃ + 3Cl₂

\overset{}{\to}

(iv) 4NH₃ + 5O₂

\overset{}{\to}

Question 15
Ozone-layer is getting depleted because of

(a) excessive use of automobiles
(b) excessive formation of industrial units
(c) excessive use of man-made compounds containing both fluorine and chlorine
(d) excessive deforestation.

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When excess of ammonia is used: 3Cl2+8NH3⟶A+BWhen excess of chlorine is used:3Cl2+4NH3⟶C+DThe oxidation state of nitrogen in compound D is:

The correct option is B +33Cl2+2NH3⟶N2(g)+HCl(g) when ammonia is excess then HCl+NH3⟶NH4Cl When chlorine in excess 2NH3( g)+3Cl2(g)⟶2 N+3Cl3(1)+6HCl(g) yellow oily liquid oxidation state of Nitrogen in compound NCl3 is +3 .

When excess of ammonia is used:

$3 C l_{2} + 8 N H_{3}$ $⟶$ $A + B$

When excess of chlorine is used:

$3 C l_{2} + 4 N H_{3}$ $⟶$ $C + D$

The oxidation state of nitrogen in compound $D$ is: