When excess of $C_{2} H_{5} O H$ at $140^{0} C$ reacts with concentrated $H_{2} S O_{4}$ , the product obtained is:

diethyl ether

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diethyl sulphate

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ethylene

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ethylene hydrogen sulphate

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Solution

The correct option is B diethyl ether
Ethyl alcohol gives diethyl ether by acid -catalysed condensation reaction.

$C_{2} H_{5} O H + H O C_{2} H_{5} c o n c . H_{2} S O_{4} - ------ \to 140^{\circ} C C_{2} H_{5} O C_{2} H_{5} + H_{2} O$

Hence, option $A$ is the correct answer.

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410 K

C_{2} H_{5} O H

140 ° C

H_{2} S O_{4}

Ethylene may be obtained by dehydration of which of the following with concentrated $H_{2} S O_{4}$ at $160 - 170^{\circ} C$ ?

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