Question

When ${\mathrm{F}}_2$ reacts with ${\mathrm{H}}_2\mathrm{S}$, Sulphur's product $\left(\mathrm{x}\right)$ is formed.

• A. ${\mathrm{SF}}_2$
• B. ${\mathrm{SF}}_4$
• C. ${\mathrm{SF}}_6$
• D. ${\mathrm{OF}}_2$

Answer 1

The correct option is C

${\mathrm{SF}}_6$

Explanation for correct option:

(C) ${\mathrm{SF}}_6$

• When three moles of fluorine react with hydrogen sulphide gives sulphur hexafluoride.
• It is nothing but a combination reaction, the sulphur and fluorine combined to form the product.

$$\begin{gathered} 3{\mathrm{F}}_2\left(\mathrm{g}\right)+{\mathrm{H}}_2\mathrm{S}\left(\mathrm{g}\right)\to {\mathrm{SF}}_6\left(\mathrm{g}\right)+{\mathrm{H}}_2\left(\mathrm{g}\right) \\ \left(\mathrm{Fluorine}\right)(\mathrm{Hydrogen}\mathrm{sulphide})(\mathrm{Sulphur}\mathrm{hexafluoride})(\mathrm{Hydrogen}\mathrm{gas}) \end{gathered}$$

So, this is the correct option.

Explanation for incorrect option:

(A) ${\mathrm{SF}}_2$

• When fluorine reacts with hydrogen sulphide sulphur hexafluoride is formed not sulphur difluoride is formed. So, this is an incorrect option.

(B) ${\mathrm{SF}}_4$

• The reaction of fluorine with hydrogen sulphide will give sulphur hexafluoride, not sulphur tetrafluoride. So, this is an incorrect option.

(D) ${\mathrm{OF}}_2$

• There is no oxygen on the reactant side. So obviously this is an incorrect option.

Therefore, the correct option is (C) ${\mathrm{SF}}_6$.