When $F e$ replaces $C u S O_{4}$ in the following reaction, what will be the ionic compound that forms between Fe and $C u S O_{4}$ ?

F e S O_{4}

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F e_{2} S O_{4}

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F e (S O_{4})_{2}

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F e_{2} (S O_{4})_{2}

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Solution

The correct option is B $F e S O_{4}$
Fe will be oxidized to $F e^{2 +}$ ions.
Ferric ions will combine with sulphate ions to form ferrous sulphate $F e (S O_{4})$ .

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Similar questions

C u S O_{4} + F e \to F e S O_{4} + C u

F e S O_{4} + Z n \to Z n S O_{4} + F e

C u S O_{4} + F e \to F e S O_{4} + C u

F e S O_{4} + Z n \to Z n S O_{4} + F e

F e + C u S O_{4} \to F e S O_{4} + C u

C u S O_{4}

C u S O_{4} + F e \to F e S O_{4} + C u

C u S O_{4}

In the following reaction, identify the substance, ‘X’ from the given options.
$F e + C u S O_{4} \to X + C u$

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