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Hess' Law

When FeCl3 ...

Question

When $F e C l_{3}$ reacts with $K_{4} [F e (C N)_{6}]$ then which of the following compound is formed.

Brown ring complex

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Sodium nitroprusside

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Turnbull's blue

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Prussion blue

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Solution

The correct option is A Prussion blue
$F e c l_{3} + K_{4} [F e (C N)_{6}] \to F e_{4} [F e (C N)_{6}]_{3}$ $\to$ (Prussion blue compound)
+ 12Kcl.
(D) Prussion blue; is correct answer.

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