Question

When forces $F_1$, $F_2$, $F_3$ are acting on a particle of mass m such that $F_2$ and $F_3$ are mutually perpendicular, then the particle remains stationary. If the force $F_1$ is now removed then the magnitude acceleration of the particle is:
(AIEEE-2002)

• A.
• B.
• C.
• D.

Answer 1

The correct option is A

For the equilibrium of the body, $F_1$ and must act opposite to $F_2$ and $F_3$ and must be equal and opposite to the resultant of $F_2$ and $F_3$. So on removing $F_1$, a = $\frac{\left(resultantof{F}_{2}and{F}_3\right)}{m}=\frac{F_1}{m}$