Question

When forces $F_1,F_2,F_3$ are acting on a particle of mass m such that $F_{2}and{F}_3$ are mutually perpendicular, then the particle remains stationary. If the force $F_1$ is now removed then the acceleration of the particle is

• A.
• B.
• C.
• D.

Answer 1

The correct option is A

For equilibrium of system, $F_1=\sqrt{F_2^2+F_3^2}as\theta ={90}^o$
In the absence of force $F_1$, Acceleration=$\frac{Netforce}{Mass}$
$=\frac{\sqrt{F_2^2+F_3^2}}{m}=\frac{F_1}{m}$