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Standard XII

Physics

Vector Component

When forces ...

Question

When forces $F_{1}, F_{2}, F_{3}$ are acting on a particle of mass $m$ such that $F_{2}$ and $F_{3}$ are mutually perpendicular, then the particle remains stationary. lf the force $F_{1}$ is now removed then acceleration of the particle is:

F_{1} / m

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F_{1} F_{3} / m F_{1}

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(F_{2} - F_{3}) / m

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F_{2} / m

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Solution

The correct option is A $F_{1} / m$
If earlier the force was zero, Then we can assume removal of force as addition of a force $F_{1}$ .
Hence, now total force is $F_{1}$ and now acceleration is $F_{1} / m$ .

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When forces F1, F2, F3 are acting on a particle of mass m such that F2 and F3 are mutually perpendicular, then the particle remains stationary. lf the force F1 is now removed then acceleration of the particle is:

The correct option is A F1/mIf earlier the force was zero, Then we can assume removal of force as addition of a force F1. Hence, now total force is F1 and now acceleration is F1/m.

When forces $F_{1}, F_{2}, F_{3}$ are acting on a particle of mass $m$ such that $F_{2}$ and $F_{3}$ are mutually perpendicular, then the particle remains stationary. lf the force $F_{1}$ is now removed then acceleration of the particle is:

The correct option is A $F_{1} / m$
If earlier the force was zero, Then we can assume removal of force as addition of a force $F_{1}$ .
Hence, now total force is $F_{1}$ and now acceleration is $F_{1} / m$ .