When forces - F 1 - F 2 - -F 3 are acting on a particle of mass m 1 the particle remains in equilibrium- If the farce - F 1 is now removed then the acceleration of the particle is -

The correct option is B → F _ 1 / m #10;[ #10; Intially Body is in Equibrium so,; #10; Net Force must be zero #34;; #10; So F⃗_ ...

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Byju's Answer

Standard XII

Physics

Acceleration

When forces ...

Question

When forces $_{1},_{2}_{3}$ are acting on a particle of mass $m_{1}$ the particle remains in equilibrium. If the farce $_{1}$ is now removed then the acceleration of the particle is :

_{1} / m

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\to {- F}_{1} / m

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_{1}

_{2} / m

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_{2} / m

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Solution

The correct option is B $\to {- F}_{1} / m$
$\begin{matrix} Intially Body is in Equibrium so, Net Force must be zero" So {\to F}_{1} + {\to F}_{2} + {\to F}_{3} = 0 \end{matrix}$
$\begin{matrix} and weget_{2} + {\to F}_{3} & = - {\to F}_{1} - (1) So, When {\to F}_{1} is removed & _{2} +_{3} = - {\to F}_{1} [from (1)] \end{matrix}$
$\begin{matrix} so accleration of m_{1} = \frac{- \to F}{m_{1}} So Ans is (B) \end{matrix}$

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When forces →F1,→F2→,F3 are acting on a particle of mass m1 the particle remains in equilibrium. If the farce →F1 is now removed then the acceleration of the particle is :

The correct option is B →−F1/ m Intially Body is in Equibrium so, Net Force must be zero" So →F1+→F2+→F3=0 and weget −→F2+→F3=−→F1−(1) So, When →F1 is removed −→F2+−→F3=−→F1[ from (1)] so accleration of m1=−→Fm1 So Ans is (B)

When forces $_{1},_{2}_{3}$ are acting on a particle of mass $m_{1}$ the particle remains in equilibrium. If the farce $_{1}$ is now removed then the acceleration of the particle is :