Question

When fused Lead bromide is electrolyzed we observe:

• A. A silver-grey deposit at the anode and a reddish-brown deposit at the cathode
• B. A silver-grey deposit at the cathode and a reddish-brown deposit at the anode
• C. A silver-grey deposit at the cathode and reddish-brown fumes at the anode.
• D. Silver grey fumes at the anode and reddish fumes at the cathode.

Answer 1

The correct option is C

A silver-grey deposit at the cathode and reddish-brown fumes at the anode.

During the process of electrolysis, Silver-grey colored lead will be deposited at the cathode, and reddish-brown bromine gas will get deposited at the anode electrodes. The reaction is,

$$\begin{gathered} Cathode:\underset{Leadion}{P{b}^{2+}}+2e^{-}\to \underset{Lead}{Pb} \\ Anode:\underset{Bromides}{2B{r}^{-}}\to \underset{Bromine}{B{r}_2}+2e^{-} \end{gathered}$$

Since Silver grey deposit of Lead is deposited at Cathode and reddish-brown fumes or gas is deposited at Anode. This option is incorrect.

Final Answer: Hence, Option (C) Is correct. When fused Lead bromide is electrolyzed we observe a silver-grey deposit at the cathode and reddish-brown fumes at the anode.