When gas (A) is passed through dry $K O H$ at low temperature, a deep red coloured compound (B) and a gas (C) are obtained. The gas A, on reaction with but-2-ene, followed by treatment with $Z n / H_{2} O$ yields acetaldehyde. (A), (B) and (C) are identified as $O_{x}$ , $K O_{y}$ and $O_{z}$ . What is $x + y + z$ ?

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Solution

Potassium hydroxide with some ozone forms $K O_{3}$ , a red coloured compound and oxygen gas.
$K O H + O_{3} ⟶ K O_{3} + O_{2} + H_{2} O$
Hence, $A$ is $O_{3}$ , $B$ is $K O_{3}$ and $C$ is $O_{2}$
$x + y + z = 3 + 3 + 2 = 8$

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When gas (A) is passed through dry KOH at low temperature, a deep red coloured compound (B) and a gas (C) are obtained. The gas A, on reaction with but-2-ene, followed by treatment with Zn/H2O yields acetaldehyde. (A), (B) and (C) are identified as Ox, KOy and Oz. What is x+y+z?

Potassium hydroxide with some ozone forms KO3, a red coloured compound and oxygen gas.KOH+O3⟶KO3+O2+H2OHence, A is O3, B is KO3 and C is O2x+y+z=3+3+2=8

Potassium hydroxide with some ozone forms $K O_{3}$ , a red coloured compound and oxygen gas.
$K O H + O_{3} ⟶ K O_{3} + O_{2} + H_{2} O$
Hence, $A$ is $O_{3}$ , $B$ is $K O_{3}$ and $C$ is $O_{2}$
$x + y + z = 3 + 3 + 2 = 8$