When a glass prism of refracting angle 60∘ is immersed in a liquid, its angle of minimum deviation is 30∘. The critical angle of glass with respect to the liquid medium is
A
30∘
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B
45∘
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C
60∘
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D
50∘
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Solution
The correct option is B45∘ μ=sin(A+dM2)sinA2=sin[60+302]sin[602]μ=sin45∘sin30∘=(1√2)(12)=√2sinC=1μ=1√2C=45∘