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Question

When glucose is treated with dilute NaOH, it gives a mixture of D-glucose and:

A
L-glucose and D-fructose
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B
D-fructose and L-mannose
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C
D-fructose and D-mannose
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D
L-fructose and L-mannose
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Solution

The correct option is D D-fructose and D-mannose
When glucose is treated with dilute NaOH, it gives a mixture of D-glucose, D-mannose and D-fructose. This reaction is known as Lobry de Bruyn-van Ekenstein rearrangement. In this reaction, glucose undergoes a reversible isomerisation.
D
-glucose D-fructose D-mannose

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