When Grignard reagent $C H_{3} M g B r$ is treated with water, we get

ethane

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ethyl alcohol

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methyl alcohol

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methane

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Solution

The correct option is D methane
Reaction of grignard reagent with water:
$C H_{3} M g B r + H_{2} O \to C H_{4} + M g (O H) B r$
So, the product obtained when grignard reagent is treated with water is methane. Here Grignard acts as strong base.

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