When gypsum is heated to 393 K, it forms

C a S O_{4} . 0.5 H_{2} O

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Dead burnt plaster

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C a S O_{4} . 5 H_{2} O

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A n h y d r o u s C a S O_{4}

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Solution

The correct option is A $C a S O_{4} . 0.5 H_{2} O$
When gypsum is heated at 393 K, it loses its water of crystallization or all the water molecules and becomes calcium sulphate hemihydrate.

$C a S O_{4} .2 H_{2} O 393. K ⟶ C a S O_{4} . \frac{1}{2} H_{2} O$

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Similar questions

When the powder of Plaster of Paris is mixed with water, it becomes hard and solid gypsum, so can't we heat it to again form P.O.P in powder form?

C a S O_{4} .2 H_{2} O

120^{0} C

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