When $H_{2}$ $O_{2}$ is added to $T i O_{2}$ solution acidified with conc. $H_{2}$ $S O_{4}$ , the orange coloured compound formed is

Ti2O3

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H2Ti2O8

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H2TiO3

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H2TiO4

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Solution

The correct option is D
H2TiO4

$T i O_{2}$ + 2 $H_{2}$ $S O_{4}$ $\to$ Ti( $S O_{4}$ ) $_{2}$ + 2 $H_{2}$ O

Ti( $S O_{4}$ ) $_{2}$ + $H_{2}$ $O_{2}$ + 2 $H_{2}$ O $\to$ $H_{2}$ $T i O_{4}$ + 2 $H_{2}$ $S O_{4}$

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When H2O2 is added to TiO2 solution acidified with conc. H2SO4, the orange coloured compound formed is

The correct option is D H2TiO4 TiO2 + 2H2SO4 → Ti(SO4)2 + 2H2O Ti(SO4)2 + H2O2 + 2H2O → H2TiO4 + 2H2SO4

When $H_{2}$ $O_{2}$ is added to $T i O_{2}$ solution acidified with conc. $H_{2}$ $S O_{4}$ , the orange coloured compound formed is

The correct option is D
H2TiO4

$T i O_{2}$ + 2 $H_{2}$ $S O_{4}$ $\to$ Ti( $S O_{4}$ ) $_{2}$ + 2 $H_{2}$ O

Ti( $S O_{4}$ ) $_{2}$ + $H_{2}$ $O_{2}$ + 2 $H_{2}$ O $\to$ $H_{2}$ $T i O_{4}$ + 2 $H_{2}$ $S O_{4}$