When $H_{2} O_{2}$ reacts with ozone, and forms $H_{2} O$ and $O_{2}$ . In this reaction $O_{2}$ is released by:

H_{2} O

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O_{3}

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H_{2} O_{2}

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O_{2}

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Solution

The correct options are
B $O_{3}$
C $H_{2} O_{2}$
$O_{3} + H_{2} O_{2} \to H_{2} O + 2 O_{2}$
Thus $O_{2}$ is released by both.

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Similar questions

H_{2} O_{2} + O_{3} \to H_{2} O + 2 O_{2}

H_{2} O_{2} + A g_{2} O \to 2 A g + H_{2} O + O_{2}

O - O

O_{2}, H_{2} O_{2}

O_{3}

The correct order of the O - O bond length in $O_{2}$ , $H_{2} O_{2}$ and $O_{3}$ is

H_{2} O_{2} + O_{3} \to H_{2} O + O_{2}

H_{2} O_{2}

Balance this equation ( I )H2O2+Mno2=H2O+O2

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