When $H_{2} S$ is passed through acidified $K M n O_{4}$ we get:

K_{2} S O_{3}

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H_{2} S O_{4}

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K H S O_{3}

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sulphur

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Solution

The correct option is A sulphur
$K M n O_{4} + H_{2} S + H_{2} S O_{4} \to H_{2} O + K_{2} S O_{4} + K O H + M n O_{2} + S$
Here $K M n O_{4}$ acts as oxidizing agent and oxidizes $H_{2} S$ to sulphur.

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When H2S is passed through acidified KMnO4 we get:

The correct option is A sulphurKMnO4+H2S+H2SO4→H2O+K2SO4+KOH+MnO2+SHere KMnO4 acts as oxidizing agent and oxidizes H2S to sulphur.

When $H_{2} S$ is passed through acidified $K M n O_{4}$ we get:

The correct option is A sulphur
$K M n O_{4} + H_{2} S + H_{2} S O_{4} \to H_{2} O + K_{2} S O_{4} + K O H + M n O_{2} + S$
Here $K M n O_{4}$ acts as oxidizing agent and oxidizes $H_{2} S$ to sulphur.