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Potassium Dichromate

When H2S is...

Question

When $H_{2} S$ is passed through $H g_{2}^{2 +}$ , we get :

H g S

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H g S + H g_{2} S

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H g S + H g

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H g_{2} S

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Solution

The correct option is C $H g S + H g$
When $H_{2} S$ is passed through $H g_{2}^{2 +}$ , we get $H g S + H g$

$H + 2 S + H g_{2}^{2 +} \to H g S + H g$

Here the $H g_{2}^{2 +}$ undergoes disproportionation reaction, in which it is reduced to $H g$ and oxidised to $H g^{2 +}$ in $H g S$ .

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H_{2} S

H g_{2}^{2 +}

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