Question

When $H_{2}S$ is passed through nitric acid solution the products formed are-

• A. $\beta -$ sulphur
• B. $\gamma -$ sulphur
• C. Colloidal sulphur
• D. Milk of sulphur

Answer 1

The correct option is C Colloidal sulphur

Nitric acid is an oxidising agent. Hence, when $H_{2}S$ is passed through $HN{O}_3$ it oxidised ($S^{2-}$) into $\left(S^o\right)$ and colloidal sulphur is formed.
$HN{O}_3+H_{2}S\to 2N{O}_2+S+2H_{2}O$
Therefore, the correct option is (c).