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Question

When heated above 916 C, iron changes its BCC crystalline form to FCC without any change in the radius of atom. The ratio of density of the crystal before heating and after heating is [atomic weight of Fe=56]

A
1.069
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B
0.918
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C
0.725
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D
1.231
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Solution

The correct option is B 0.918
We know that,
Density = d =Z×MMa3×NA
The ratio of density of the crystal before heating and after heating is
d1d2=ZBCC×MMa3BCC×NAZFCC×MMa3FCC×NA
=ZBCCa3BCCa3FCCZFCC
=2(4r3))3×(22r)34
= 0.918


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