When heated in air, brown copper powder turns black. This black powder would turn brown again when heated with:

C O

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O_{2}

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H_{2}

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N H_{3}

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Solution

The correct option is C $H_{2}$
$2 C u + O_{2} \to 2 C u O$

$C u O$ is black in colour. When hydrogen is passed over it, hydrogen displaces oxygen from oxide which restores the brown colour of the copper.
Here, $H_{2}$ acts as a reducing agent.

$C u O + H_{2} \to C u + H_{2} O$

Hence, option C is correct.

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When heated in air, brown copper powder turns black. This black powder would turn brown again when heated with:

The correct option is C H22Cu+O2→2CuO CuO is black in colour. When hydrogen is passed over it, hydrogen displaces oxygen from oxide which restores the brown colour of the copper.Here, H2 acts as a reducing agent.CuO+H2→Cu+H2OHence, option C is correct.