When heated, potassium permanganate decomposes according to the following equation:

Given that the molecular mass of potassium permanganate is 158, what volume of oxygen (measured at room temperature) would be obtained by the complete decomposition of 15.8 g of potassium permanganate? (Molar volume at room temperature is 24 litres.)

1.3 litres

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5.6 litres

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3.1 litres

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.2 litres

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1.4 litres

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D
1.2 litres

Suggest Corrections

Similar questions

When heated, potassium permanganate decomposes according to the following equation:

$2 K M n O_{4} \to K_{2} M n O_{4} + M n O_{2} + O_{2}$

Given that the molecular mass of potassium permanganate is $158$ , what volume of oxygen (measured at room temperature) would be obtained by the complete decomposition of $15.8$ g of potassium permanganate? (Molar volume at room temperature is $24$ liters.)

When heated, potassium permanganate decomposes according to the following equation:
2KMnO₄ $\overset{}{\to}$ K₂MnO₄ + MnO₂ + O₂
(a) Some potassium permanganate was heated in a test tube. After collecting one litre of oxygen at room temperature, it was found that the test tube had undergone a loss in mass of 1.32 g. If one litre of hydrogen under the same conditions of temperature and pressure has a mass of 0.0825 g, calculate the relative molecular mass of oxygen.
(b) Given that the molecular mass of potassium permanganate is 158 g, what volume of oxygen (measured at room temperature) would be obtained by the complete decomposition of 15.8 g of potassium permanganate? (Molar volume at room temperature is 24 litres). (K = 39, Mn = 55, O = 16)

When heated, potassium permanganate decomposes according to the following equation:

Some potassium permanganate was heated in a test tube. After collecting one litre of oxygen at room temperature, it was found that the test tube had undergone a loss in mass of 1.32 g. If one litre of hydrogen under the same conditions of temperature and pressure has a mass of 0.0825 g, calculate the relative molecular mass of oxygen.

Q. What is the colour of the mass obtained when potassium permanganate is decomposed?

Q. Some potassium permanganate was heated in a test tube. After collecting one litre of oxygen at room temperature, it was found that the test tube had undergone a loss in mass of

1.32 g

. If one litre of hydrogen under the same conditions of temperature and pressure has a mass of

0.0825 g

.
Calculate the relative molecular mass of oxygen.

Join BYJU'S Learning Program

The correct option is D 1.2 litres

The correct option is D
1.2 litres