When hydrochloric acid gas is treated with propene in presence of benzoyl proxide, it gives:

2-Chloropropane

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Allyl chloride

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n-Propyl chloride

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None of the above

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Solution

The correct option is A 2-Chloropropane
Peroxide effect is observed only in case of HBr. Therefore addition of HCl to propene even in the presence of benzyoyl peroxide occurs according to Markovnikov's rule:
$C H_{3} - C H = C H_{2} H C l - -------- \to (C_{6} H_{5} C O)_{2} O_{2} C H_{3} - C H C l - C H_{3}$

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