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Hydrogen Spectra

When hydrogen...

Question

When hydrogen atom absorbs a photon of wavelength $60 n m$ , photo-ionization of atom occurs. The maximum kinetic energy of emitted electrons will be-

A

13.6 eV

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B

7.1 eV

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C

3.6 eV

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D

1.9 eV

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Solution

The correct option is B 7.1 eV
Hydrogen atom means ionization energy $E_{i} = 13.6 e V$
Energy of incident photon is $E = \frac{1237.5}{60} e V = 20.625 e V$
Extra energy after ionization is $E - E_{i} = 7.025 e V$
Option B is correct.

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