When I am as old my father is now, I shall be five times as old as my son is now. By then, my son will be 8 years older than I am now. The combined age of my father and myself is 100 years. How old is my son ?
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Solution
Let my son's age and my age be x and y, respectively.
Therefore, my father's age is 5x ⇒5x+y=100 ....(i) Number of years I will take to reach my father's age =5x−7
In (5x−7) years, my son's age will become x+5x−y=6x−y
It is given that 6x−y=y+8
⇒6x−2y=8 ...........(ii) Solving (i) and (ii) we get,