Question

When intermolecular attractive forces are neglected, isobar formed between V and T at constant p is of the type given in the figure.
Pressure at which isobar made is:

• A. 2 atm
• B. 0.5 atm
• C. 1 atm
• D. 4 atm

Answer 1

The correct option is B 0.5 atm

$\Rightarrow PV=nRT$

$Pv\times {10}^{-1}=nRT$ (volume is litre)

$P=\frac{nR}{tan\theta \times {10}^{-1}}$

$\{tan\theta =slope=\frac{V}{T}(ind{m}^3\left)\right\}$

putting n = 1, R = 0.082ltatm/mole x

$=\frac{0082}{0.1642}\times 10=\frac{0.82}{0.1642}=0.5atm$