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Byju's Answer
Standard XII
Chemistry
Calcination
When K2Cr2O...
Question
When
K
2
C
r
2
O
7
crystals are heated with conc.
H
C
l
, the gas evolved is :
A
O
2
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B
C
l
2
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C
C
r
O
2
C
l
2
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D
H
C
l
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Solution
The correct option is
B
C
l
2
Chlorine can be prepared as follows:
K
2
C
r
2
O
7
+
14
H
C
l
H
e
a
t
−
−−
→
2
K
C
l
+
2
C
r
C
l
3
+
7
H
2
O
+
3
C
l
2
Hence the chlorine gas is liberated .
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