When $K_{2} C r_{2} O_{7}$ is converted to $K_{2} C r O_{4}$ the change in the oxidation state of chromium is

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Solution

The correct option is A
0

$K_{2} + 6 C r_{2} O_{7} \to K_{2} + 6 C r_{2} O_{4}$ . In this reaction, there is no change in oxidation state of chromium.

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Similar questions

When $K_{2} C r_{2} O_{7}$ is converted to $K_{2} C r O_{4}$ the change in the oxidation state of chromium is

K_{2} C r_{2} O_{7}

K_{2} C r O_{4},

K_{2} {C r}_{2} O_{7}

K_{2} C r O_{4}

K_{2} C r_{2} O_{7}

S O_{2}

K_{2} C r_{2} O_{7}

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