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Chemical Equilibrium in Reversible Reactions

When K4[FeC...

Question

When $K_{4} [F e (C N)_{6}]$ is treated with $F e C l_{3}$ , a blue color is obtained.

It is due to the formation of :

F e^{I I} [F e^{I I I} (C N)_{6}]^{-}

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F e^{I I I} [F e^{I I} (C N)_{6}]^{-}

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Both (a) and (b)

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None of these

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Solution

The correct option is C Both (a) and (b)
When $K_{4} [F e (C N)_{6}]$ is treated with $F e C l_{3}$ , a blue color is obtained.

It is due to the formation of $F e^{I I} [F e^{I I I} (C N)_{6}]^{-}$ and $F e^{I I I} [F e^{I I} (C N)_{6}]^{-}$ .

$4 F e C l_{3} + 3 K_{4} [F e (C N)_{6}] \to F e_{4} [F e (C N)_{6}]_{3} + 12 K C l$

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Similar questions

F e C l_{3}

K_{4} [F e (C N)_{5}]

F e^{I I I} [F e^{I I} (C N)_{6}]^{-}, F e^{I I} [F e^{I I I} (C N)_{6}]^{-}

F e C l_{2}

K_{3} [F e (C N)_{6}]

F e^{I I} [F e^{I I I} (C N)_{6}]^{-}, F e^{I I I} [F e^{I I} (C N)_{6}]^{-}

F e^{I I I} [F e^{I I} (C N)_{6}]^{-}

F e^{I I} [F e^{I I I} (C N)_{6}]^{-}

F e^{I I I} [F e^{I I} (C N)_{6}]^{-}

F e^{I I} [F e^{I I I} (C N)_{6}]^{-},

{F e}^{I I} [{F e}^{I I} ({C N)}_{6}]^{2 -}

{F e}^{I I I} [{F e}^{I I I} ({C N)}_{6}]

{F e}^{I I} [{F e}^{I I I} ({C N)}_{6}]^{-}

{F e}^{I I I} [{F e}^{I I} ({C N)}_{6}]^{-}

F e C l_{3}

K_{4} [F e (C N)_{6}]

K_{4} [F e (C N)_{6}]

F e C l_{3}

K_{4} [F e (C N)_{6}]

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