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Introduction to Oxidation and Reduction

When KClO3 ...

Question

When $K C l O_{3}$ is heated in presence $M n O_{2}$ the product is:

O_{2}

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C l_{2}

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O_{3}

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none of these

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Solution

The correct option is A $O_{2}$
When $K C l O_{3}$ is reacted with $M n O_{2}$ in presence of heat it forms $K C l, O_{2}, M n O_{2}$ respectively.
$K C l O_{3} + M n O_{2} ⟶ K C l + O_{2} + M n O_{2}$
Hence option A is correct.

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Similar questions

K C l O_{3}

M n O_{2}

H N O_{3}

M n O_{2} + 2 K C l O_{3} ⟶ K_{2} M n O_{4} + C l_{2} + 2 O_{2}

C l_{2} + K M n O_{4} ⟶ 2 K C l + M n O_{2} + O_{2}

50 %

11.2

O_{2}

K C l O_{3}

M n O_{2} + 2 K C l O_{3} \to K_{2} M n O_{4} + C l_{2} + 2 O_{2}

C l_{2} + K_{2} M n O_{4} \to 2 K C l + M n O_{2} + O_{2}

O_{2}

K C l O_{3}

K C l O_{3}

M n O_{2}

M n O_{2} + 2 K C l O_{3} ⟶ K_{2} M n O_{4} + C l_{2} + 2 O_{2}

C l_{2} + K M n O_{4} ⟶ 2 K C l + M n O_{2} + O_{2}

50 %

11.2

O_{2}

K C l O_{3}

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