Question

When $KMn{O}_4$ reacts with $H_2{O}_2$ in acidic medium then which of the following is formed?

• A. $M{n}^{+2}$
• B. $M{n}^{+7}$
• C. $Mn{O}_2$
• D. $M{n}_2{O}_3$

Answer 1

The correct option is A $M{n}^{+2}$

The reaction of $KMn{O}_4$ with $H_2{O}_2$ in acidic medium is as follows:

Balanced reaction is:

$5H_2{O}_2+2kMn{O}_4+3H_{2}S{O}_4\to 5O_2+2MnS{O}_4+K_{2}S{O}_4+8H_{2}O$

In $MnS{O}_4$, $Mn$ is in +2 oxidation state, hence ${Mn}^{2+}$ is formed.

$[\underset{+7}{KMn{O}_4}\to \underset{+2}{MnS{O}_4}]$.