When $K M n O_{4}$ acts as an oxidising agent and forms $M n^{+ 2}$ , the number of electrons transferred per molecule of $K M n O_{4}$ is :

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Solution

Reaction when $K M n O_{4}$ acts as an oxidising agent and forms $M n^{2 +}$ is given below:
$+ 7 M n O_{4}^{-} + 5 e \to + 2 M n$
The oxidation state of $M n$ in $M n O_{4}^{-}$ and $M n^{2 +}$ are $+ 7$ and $+ 2$ respectively.
Therefore, change in oxidation is $5$ which is the number of electrons transferred per molecule.

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When KMnO4 acts as an oxidising agent and forms Mn+2, the number of electrons transferred per molecule of KMnO4 is :

Reaction when KMnO4 acts as an oxidising agent and forms Mn2+ is given below:+7MnO−4+5e→+2MnThe oxidation state of Mn in MnO−4 and Mn2+ are +7 and +2 respectively.Therefore, change in oxidation is 5 which is the number of electrons transferred per molecule.

When $K M n O_{4}$ acts as an oxidising agent and forms $M n^{+ 2}$ , the number of electrons transferred per molecule of $K M n O_{4}$ is :