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Oxidising Reagent and Reducing Reagent

When KMnO 4 a...

Question

When $K M n O_{4}$ acts as an oxidising agent and ultimately forms $[M n O_{4}]^{2 -}, M n O_{2}, M n_{2} O_{3}, M n^{2 +}$ then the number of electrons transferred in each case respectively is

A

4, 3, 1, 5

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B

1, 5, 3, 7

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C

1, 3, 4, 5

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D

3, 5, 7, 1.

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Solution

The correct option is C 1, 3, 4, 5

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Similar questions

K M n O_{4}

acts as an oxidising agent and ultimately forms

[M n O_{4}^{2 -}, M n O_{2}, M n_{2} O_{3}]

M n^{+ 2} .

Then the number of electrons transferred in each case respectively is:

K M n O_{4}

acts as an oxidising agent and ultimately forms

[M n O_{4}]^{2 -}

M n O_{2}

M n_{2} O_{3}

M n^{2 +}

, then the number of electrons transferred in each case respectively is:

K M n O_{4}

acts as an oxidising agent and ultimately forms

[M n O_{4}]^{- 1}

M n O_{2}

M n_{2} O_{3}

M n_{2} O^{+}

, then the number of electrons transferred in each case respectfully is

K M n O_{4}

acts as an oxidising agent and ultimately forms

M n O_{4}^{2 -}, M n O_{2}, M n_{2} O_{3}

M n^{2 +}

, then the number of electrons transferred in each case respectively are:

k M n O_{4}

acts as an oxidising agent and ultimately forms

M n O_{4}^{2 -}, M n O_{2}, M n_{2} O_{3},

M n^{2 +}

, determine the number of electrons transferred in each case.

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