Question

When $KMn{O}_4$ acts as an oxidising agent and ultimately forms $[Mn{O}_4{]}^{2-}$, $Mn{O}_2$, $M{n}_2{O}_3$, $M{n}^{2+}$, then the number of electrons transferred in each case respectively is:

• A. 4, 3, 1, 5
• B. 1, 5, 3, 7
• C. 1, 3, 4, 5
• D. 3, 5, 7, 1

Answer 1

The correct option is C 1, 3, 4, 5

${KMnO}_4\stackrel{+1e}{\to }[Mn{O}_4{]}^{2-}$

${KMnO}_4\stackrel{+3e}{\to }Mn{O}_2$

${KMnO}_4\stackrel{+4e}{\to }{Mn}_2{O}_3$

${KMnO}_4\stackrel{+5e}{\to }{Mn}^{2+}$

Option C is correct.