CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

When KMnO4 acts as an oxidizing agent and ultimately forms MnO24, MnO2, Mn2O3 and Mn2+ then the number of electrons transferred in each case respectively are:

A
1, 3, 4, 5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1, 5, 3, 7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4, 3, 2, 1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3, 2, 1, 4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 1, 3, 4, 5
The oxidation state of Mn in MnO4 is +7.
The oxidation state of Mn in MnO24 is +6.
The oxidation state of Mn in MnO2 is +4.
The oxidation state of Mn in Mn2O3 is +3.
The oxidation state of Mn in Mn2+ is +2.

The number of transfer of electron from MnO4 to MnO24 is 1.
The number of transfer of electron from MnO4 to MnO2 is 3.
The number of transfer of electron from MnO4 to Mn2O3 is 4.
The number of transfer of electron from MnO4 to Mn2+is 5.

Hence, option (a) is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Redox Reactions
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon