When $K M n O_{4}$ is heated with fused KOH, then the product formed is

K M n O_{4}, p u r p l e

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K_{2} M n O_{4}, g r e e n

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M n O_{2}, b l a c k

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M n_{2} O_{3}, b r o w n

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Solution

The correct option is D $K_{2} M n O_{4}, g r e e n$
$K M n O_{4} + K O H Δ \to K_{2} M n O_{4} + H_{2} O$
green
It is a redox reaction where Mn is reduced from +7 to +6

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When KMnO4 is heated with fused KOH, then the product formed is

The correct option is D K2MnO4,greenKMnO4+KOHΔ→K2MnO4+H2O greenIt is a redox reaction where Mn is reduced from +7 to +6

When $K M n O_{4}$ is heated with fused KOH, then the product formed is

The correct option is D $K_{2} M n O_{4}, g r e e n$
$K M n O_{4} + K O H Δ \to K_{2} M n O_{4} + H_{2} O$
green
It is a redox reaction where Mn is reduced from +7 to +6