When KMnO $_{4}$ reacts with KBr in alkaline medium bromine ion is formed. The oxidation state of Mn changes from $+ 7$ to:

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Solution

The correct option is A 4
In alkaline medium, ${M n O}_{4}^{2 -}$ forms ${M n O}_{2}$
$+ 7$ $+ 4$
$∴$ ${M n O}_{4}^{-} ⟶ {M n O}_{2}$ (in alkaline medium)
Therefore, the oxidation state of $M n$ changes from $+ 7$ to $+ 4$ in alkaline medium.

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