When $K M n O_{4}$ reacts with $K B r$ in alkaline medium gives bromate ion. Then oxidation state of $M n$ changes from $+ 7$ to :

+ 6

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+ 4

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+ 3

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+ 2

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Solution

The correct option is A $+ 4$
$+ 7 2 M n O_{4}^{-} + B r^{-} + H_{2} O \to + 4 2 M n O_{2} + B r O_{3}^{-} + 2 O H^{-}$

$∴$ Oxidation state changes to +4.

Suggest Corrections

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