When light falls on a photo diode, its conductivity increases. Experimentally, it is found that the conductivity changes only when the wavelength of the incident light is less than $620 nm$ . The band gap of the diode is-

0.75 eV

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1.1 eV

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1.5 eV

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2.0 eV

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Solution

The correct option is D $2.0 eV$
Given, $λ = 620 nm$

Energy band gap $E_{g}$ is,

$E_{g} = \frac{h c}{λ}$

$E_{g} = \frac{1240}{λ (m)} = \frac{1240}{620} = 2 eV$

 Hence, $(D)$ is the correct answer.

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When light falls on a photo diode, its conductivity increases. Experimentally, it is found that the conductivity changes only when the wavelength of the incident light is less than 620 nm. The band gap of the diode is-

The correct option is D 2.0 eVGiven, λ=620 nm Energy band gap Eg is, Eg=hcλ Eg=1240λ(m)=1240620=2 eV  Hence, (D) is the correct answer.

When light falls on a photo diode, its conductivity increases. Experimentally, it is found that the conductivity changes only when the wavelength of the incident light is less than $620 nm$ . The band gap of the diode is-

The correct option is D $2.0 eV$
Given, $λ = 620 nm$

Energy band gap $E_{g}$ is,

$E_{g} = \frac{h c}{λ}$

$E_{g} = \frac{1240}{λ (m)} = \frac{1240}{620} = 2 eV$

 Hence, $(D)$ is the correct answer.