When light passes from A to B- the value of sin i-sin r is greater than 1- It implies that the light ray bends towards the normal-

We know that, sin i/sin r = v_1/v_2. If the value is greater than 1, it implies; v_1 gt; v_2. So, in medium B, light travels with a lesser velocity, implying ...

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Standard XII

Physics

History of Snell's Law

When light pa...

Question

When light passes from A to B, the value of $\frac{s i n i}{s i n r}$ is greater than 1. It implies that the light ray bends towards the normal.

True

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False

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Solution

The correct option is A
True

We know that,
$\frac{s i n i}{s i n r} = \frac{v_{1}}{v_{2}} .$
If the value is greater than 1, it implies;
$v_{1} > v_{2} .$
So, in medium B, light travels with a lesser velocity, implying that medium B is denser than medium A . Therefore, the ray will bends towards the normal.

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When light passes from A to B, the value of sin isin r is greater than 1. It implies that the light ray bends towards the normal.

The correct option is A True We know that, sin isin r=v1v2. If the value is greater than 1, it implies; v1>v2. So, in medium B, light travels with a lesser velocity, implying that medium B is denser than medium A . Therefore, the ray will bends towards the normal.

When light passes from A to B, the value of $\frac{s i n i}{s i n r}$ is greater than 1. It implies that the light ray bends towards the normal.